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The numeric value of a lowercase character is defined as its position (1-indexed) in the alphabet, so the numeric value of a is 1, the numeric value of b is 2, the numeric value of c is 3, and so on.
The numeric value of a string consisting of lowercase characters is defined as the sum of its charactersβ numeric values. For example, the numeric value of the string βabeβ is equal to 1 + 2 + 5 = 8.
You are given two integers n and k. Return the lexicographically smallest string with length equal to n and numeric value equal to k.
Note that a string x is lexicographically smaller than string y if x comes before y in dictionary order, that is, either x is a prefix of y, or if i is the first position such that x[i] != y[i], then x[i] comes before y[i] in alphabetic order.
class Solution {
public:
string getSmallestString(int n, int k)
{
string ans = "";
for (int i = 0; i < n; i++) {
ans += 'a';
}
k -= n;
int i = 0;
while (k != 0) {
if (k >= 25) {
ans[i++] = 'z';
k -= 25;
} else {
ans[i] = ans[i] + k;
i++;
reverse(ans.begin(), ans.end());
return ans;
}
}
reverse(ans.begin(), ans.end());
return ans;
}
};