100. Same Tree 🌟

Given the roots of two binary trees p and q, write a function to check if they are the same or not.

Two binary trees are considered the same if they are structurally identical, and the nodes have the same value.

Intuitive recursive solution

• self explanatory

class Solution {
public:
    bool isSameTree(TreeNode* p, TreeNode* q)
    {
        if (p == NULL && q == NULL) return true;
        if (p == NULL || q == NULL) return false;
        if (p->val != q->val) return false;
        return isSameTree(p->left, q->left) && isSameTree(p->right, q->right);
    }
};

Recursive to iterative using queue

class Solution {
private:
    bool check(TreeNode* left, TreeNode* right)
    {
        if (left == NULL || right == NULL) return false;
        if (left->val != right->val) return false;
        return true;
    }

public:
    bool isSameTree(TreeNode* p, TreeNode* q)
    {
        if (p == NULL && q == NULL) return true;
        if (check(p, q) == false) return false;
        queue<TreeNode*> q1, q2;
        q1.push(p);
        q2.push(q);

        while (q1.empty() == false) {
            TreeNode* left = q1.front(); q1.pop();
            TreeNode* right = q2.front(); q2.pop();

            if (left == NULL && right == NULL) continue;
            if (check(left, right) == false) return false;

            q1.push(left->left);
            q1.push(left->right);
            q2.push(right->left);
            q2.push(right->right);
        }
        return true;
    }
};